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x^2-(1.4)x+0.4=0
We multiply parentheses
x^2-1.4x+0.4=0
a = 1; b = -1.4; c = +0.4;
Δ = b2-4ac
Δ = -1.42-4·1·0.4
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.4)-\sqrt{0.36}}{2*1}=\frac{1.4-\sqrt{0.36}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.4)+\sqrt{0.36}}{2*1}=\frac{1.4+\sqrt{0.36}}{2} $
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